1046. Last Stone Weight

time: nlog(n)
space: O(n)
class Solution {
public int lastStoneWeight(int[] stones) {
PriorityQueue<Integer> pq = new PriorityQueue<>(Collections.reverseOrder());
for (int s : stones) {
pq.offer(s);
}
while (pq.size() > 1) {
pq.offer(pq.poll() - pq.poll());
}
return pq.poll();
}
}
Last updated
Was this helpful?