```java
class Solution {
public String findDifferentBinaryString(String[] nums) {
StringBuilder result = new StringBuilder();
for (int i = 0; i < nums.length; i++) {
if (nums[i].charAt(i) == '0') {
result.append('1');
} else {
result.append('0');
}
}
return result.toString();
}
}
/**
T: O(n)
S: O(n)
01. 10
/. \
1 1. -> ans!!!
["111","011","001"]
/ | \
0 0 0 -> ans!!!!
*/
```