925. Long Pressed Name

class Solution {
    public boolean isLongPressedName(String name, String typed) {
        int n = 0;
        int nameLen = name.length();
        int typedLen = typed.length();
        for (int t = 0; t < typedLen; t++) {
            if (n < nameLen && name.charAt(n) == typed.charAt(t)) {
                n++;
            } else if (t > 0 && typed.charAt(t-1) != typed.charAt(t)) {
                return false;
            }
        }
        return n == nameLen;
    }
}